Q.
A string of length $L$ is fixed at one end and the string makes $\frac{2}{\pi}$ rev/s around the vertical axis through, the fixed and as shown in the figure, then tension in the string is
A) $ML$
B) $2\ ML$
C) 4$\ ML$
D) 16$\ ML$
Explanation
(d) $T\sin\theta = M\omega^{2}R$ …(i)
$T\sin\theta = M\omega^{2}L\ sin\ \theta$ …(ii)
$T = M\omega^{2}L$
$= M \bullet 4\pi^{2}n^{2}L$
$= M \bullet 4\pi^{2}\left( \frac{2\ ^{\ }}{\pi} \right)^{2}L$
$= 16\ ML$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.