A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v_{A},v_{B}$ and $v_{D}$ are speed at position $A,B$ and $D$ then [image:4_image62.emf]

Question

Dr. Abubacker · Accepted Answer

(d) At $A,\ v_{A} = \sqrt{gl}$
At $B,\ v_{B} = \sqrt{5gl}$
and at $D,\ v_{D} = \sqrt{3gl}$
Thus, $v_{B} > v_{D} > v_{A}$
Also, $T = 3\ mg(1 + \cos	heta)$
So, $D,$ $	heta = 90{^\circ}$
$	herefore\ T = 3\ mg(1 + 	heta) = 3\ mg$

Q. A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v_{A},v_{B}$ and $v_{D}$ are speed at position $A,B$ and $D$ then

Explanation

Reviewed by Dr. Abubacker

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