Q. An object is projected at an angle of $45{^\circ}$ with the horizontal. The horizontal range and the maximum height reached will be in the ratio
A) $1\ :2$
B) $2\ :1$
C) $1\ :4$
D) $4\ :1$
Explanation
(d) $R = 4H\cot\theta,$ if $\theta = 45{^\circ}$ then $R = 4H \Rightarrow \frac{R}{H} = \frac{4}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.