Q. A toy cyclist completes one round of a square track of side 2 m in 40 s. What will be the displacement at the end of 3 min?
A) 52 m
B) Zero
C) 16 m
D) $2\sqrt{2}\ m$
Explanation
(d) Displacement is distance from initial to final position In 40s cyclist completes =1 round
$\therefore In\ 3\min{(180\ s)\ cyclist\ will\ complete = 4\frac{1}{2}}\ round\ Displacement\ for\ 4\ round\ is\ zero.$
$Displacement\ for\ \frac{l}{2}\ round = length\ of\ diagonal = 2\sqrt{2}m.\ $
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.