Q. The area of parallelogram formed from the vectors $\overrightarrow{A} = \widehat{i} - 2\widehat{j} + 3\widehat{k}$ and $\overrightarrow{B} = 3\widehat{i} - 2\widehat{j} + \widehat{k}$ as adjacent sides is

A) $8\sqrt{3}$ units
B) $64$ units
C) 32 units
D) $4\sqrt{6}$ units
Explanation

(d) $\overrightarrow{A} \times \overrightarrow{B} = \left( \widehat{i} - 2\widehat{j} + 3\widehat{k} \right) \times (3\widehat{i} - 2\widehat{j} + \widehat{k})$
$= - 2\widehat{k} - \widehat{j} - 6\left( - \widehat{k} \right) - 2\widehat{i} + 9\widehat{j} - 6\left( - \widehat{i} \right) = 4\widehat{i} + 8\widehat{j} + 4\widehat{k}$
Modulus is $\sqrt{4^{2} + 8^{2} + 4^{2}} = \sqrt{32 + 64}$
$= \sqrt{96} = 4\sqrt{6}$ units.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.