(b) $H = \frac{u^{2}\sin^{2}\theta}{2g}$ $dH = \frac{2u^{\ }\sin^{2}\theta}{2g}du$ $\therefore\ \ \frac{dH}{H} = \frac{2du}{u} = 2 \times \frac{1}{10}$ $\therefore$% increase in $H = \frac{dH}{H} \times 100$ $= \frac{2}{10} \times 100 = 20\%$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.