Q. What should be the coefficient of friction between the tyres and the road, when a car travelling at 60 $km\ h^{- 1}$ makes a level turn of radius 40 m?
A) 0.5
B) 0.66
C) 0.71
D) 0.80
Explanation
(c) $\mu = \frac{v^{2}}{rg} = \frac{(60 \times 5/18)^{2}\ \ \ }{40 \times 9.8} = 0.71$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.