An aeroplane is flying in a horizontal direction with a velocity $600kmh^{- 1}$ at a height of 1960 m. when it is vertically above the point $A$ on the ground, a body is dropped from it. The body strikes the ground at point $B$. Calculate the distance $AB$. [image:4_image63.emf]

Question

Dr. Abubacker · Accepted Answer

(a) From $h = \frac{1}{2}gt^{2}$
We have $t_{OB} = \sqrt{\frac{2h_{OA}}{g}}$
$= \sqrt{\frac{2 	imes 1960}{9.8}} = 20s$
Horizontal distance $AB = vt_{OB}$
$= \left( 600 	imes \frac{5}{18} ight)(20)$
$= 3333.33\ m = 3.33\ km$

Q. An aeroplane is flying in a horizontal direction with a velocity $600kmh^{- 1}$ at a height of 1960 m. when it is vertically above the point $A$ on the ground, a body is dropped from it. The body strikes the ground at point $B$. Calculate the distance $AB$.

Explanation

Reviewed by Dr. Abubacker

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