(a) $\overrightarrow{A} \bullet \overrightarrow{B} = 0 \Rightarrow \overrightarrow{A}\bot\overrightarrow{B}$
Now, $\overrightarrow{A} \times \overrightarrow{B} = \overrightarrow{1}$ or $AB\ sin\theta = 1$
$AB\ \sin 90{^\circ} = 1$ or $AB = 1 \Rightarrow A = 1$ and $B = 1$
So, $\overrightarrow{A}$ and $\overrightarrow{B}$ are perpendicular unit vectors.