Q. A coin placed on a rotating turn table just slips if it is placed at a distance of 8 cm from the centre. If angular velocity of the turn table is doubled, it will just slip at a distance of

A) 1 cm
B) 2 cm
C) 4 cm
D) 8 cm
Explanation

(b) We know, $F = mr\omega^{2}$
$r\omega^{2} =$constant
$\omega^{2} \propto \frac{1}{r}$
$\left( \frac{\omega_{2}}{\omega_{1}} \right)^{2} = \frac{r_{1}}{r_{2}}$
$\frac{4\omega_{1}^{2}}{\omega_{1}^{2}} = \frac{8}{r_{2}}\ \ \ \therefore r_{2} = 2$ cm

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.