A stone is thrown with a velocity $v$ making an angle $ heta$ with the horizontal. At some instant, its velocity $V$ is perpendicular to the initial velocity $v$. Then $V$ is

Question

A stone is thrown with a velocity $v$ making an angle $	heta$ with the horizontal. At some instant, its velocity $V$ is perpendicular to the initial velocity $v$. Then $V$ is

Dr. Abubacker · Accepted Answer

(d) Equating horizontal components, we get
$V\cos(90{^\circ} - 	heta) = v\cos	heta$
or $V\sin	heta = v\cos	heta\ \ \ or\ \ \ V = v\cot	heta$
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Q. A stone is thrown with a velocity $v$ making an angle $\theta$ with the horizontal. At some instant, its velocity $V$ is perpendicular to the initial velocity $v$. Then $V$ is

Explanation

Reviewed by Dr. Abubacker

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