Q. The angular speed of a car increases from 600 rpm to 1200 rpm in 10 s. What is the angular acceleration of the car?
A) 600 $rad\ s^{- 1}$
B) 60 $rad\ s^{- 1}$
C) 60 $\pi$ $rad\ m\ s^{- 1}$
D) $2\ \pi\ $rad $s^{- 1}$
Explanation
(d) $\alpha = \frac{\omega_{2} - \omega_{1}}{t} = \frac{2\pi v_{2} - 2\pi v_{1}}{t}$
$= \frac{2\pi\left( \frac{1200}{60} - \frac{600}{60} \right)}{10} = 2\pi$ rad$s^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.