Q. A particle of mass 100 g tied to a string is rotated along circle of radius 0.5 m. The breaking tension of string is 10 N. The maximum speed with which particle can rotated without breaking the string is
A) 10 $ms^{- 2}$
B) 9.8 $ms^{- 2}$
C) 7.7 $ms^{- 2}$
D) 7.07 $ms^{- 2}$
Explanation
(d) Centripetal force, $F = \frac{mv^{2}}{r}$
$v = \sqrt{\left( \frac{rF}{m} \right)} = \sqrt{\frac{0.5 \times 10 \times 1000}{100}}$
$= \sqrt{50}ms^{- 1} = 7.07ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.