Q. A mass $m$ is attached to the end of a rod of length $l$. The mass goes along a vertical circular path with the other end hinged at its centre. What should be the minimum velocity of the mass at the bottom of the circle so that the mass completes the circle?

A) $\sqrt{5gl}$
B) $\sqrt{2gl}$
C) $\sqrt{3gl}$
D) $\sqrt{4gl}$
Explanation

(d) As the mass is attached to the end of a rod. Which does not stacken, therefore, taking $v = 0$ at the highest point, from $v^{2} - u^{2} = 2a\ s$
$0 - u^{2} = 2( - g)2l$
$\therefore u = \sqrt{4gl}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.