Q.
Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v_{0}$, then the ratio of tensions in the three sections of the string is
A) $3\ :5\ :7$
B) $3\ :4\ :5$
C) $7\ :11\ :6$
D) $3\ :5\ :6$
Explanation
(d) Let $\omega$ is the angular speed of revolution
$T_{3} = m\omega^{2}3l$
$T_{2} - T_{3} = m\omega^{2}2l \Rightarrow T_{2} = m\omega^{2}5l$
$T_{1} - T_{2} = m\omega^{2}l \Rightarrow T_{1} = m\omega^{2}6l$
$T_{3}:T_{2}:T_{1} = 3\ :5\ :6$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.