Q. A mass of $100\ gm$ is tied to one end of a string $2\ m$ long. The body is revolving in a horizontal circle making a maximum of 200 revolutions per min. The other end of the string is fixed at the centre of the circle of revolution. The maximum tension that the string can bear is (approximately)
A) $8.76\ N$
B) $8.94\ N$
C) $89.42\ N$
D) $87.64\ N$
Explanation
(d) Maximum tension $= m\omega^{2}r = m \times 4\pi^{2} \times n^{2} \times r$
By substituting the values we get $T_{\max} = 87.64\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.