In figure, a particle is placed at the highest point $A$ of a smooth sphere of radius $r$. It is given slight push, and it leaves the sphere at $B$, at a depth $h\ $vertically below $A$ such that $h$ is equal to [image:4_image71.emf]

Question

Dr. Abubacker · Accepted Answer

(c) If $v$ velocity acquired at $B$, then
$v^{2} = 2gh$
The particle will leave the sphere at $B$, when
$\frac{mv^{2}}{r} \geq mg\cos	heta$
$\frac{2gh}{r} = \frac{g(r - h)}{r},$
[image:4_image161.emf]
Which gives $h = \frac{r}{3}$

Q. In figure, a particle is placed at the highest point $A$ of a smooth sphere of radius $r$. It is given slight push, and it leaves the sphere at $B$, at a depth $h\ $vertically below $A$ such that $h$ is equal to

Explanation

Reviewed by Dr. Abubacker

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