Q. The magnitude of the vectors product o two vectors is $\sqrt{3}$ times their scalar product. The angle between the two vectors is
A) 90${^\circ}$
B) 60${^\circ}$
C) 45${^\circ}$
D) 30${^\circ}$
Explanation
(b) Given , $\left| \overrightarrow{A} \times \overrightarrow{B} \right| = \sqrt{3}\overrightarrow{A} \bullet \overrightarrow{B}$
$AB$ sin $\theta = \sqrt{3}\ \ \ AB$ cos $\theta$
or tan$\theta = \sqrt{3}$
$\theta = 60{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.