Q. A $100\ kg$ car is moving with a maximum velocity of $9\ m/s$ across a circular track of radius $30\ m.$ The maximum force of friction between the road and the car is
A) $1000\ N$
B) $706\ N$
C) $270\ N$
D) $200\ N$
Explanation
(c) Maximum force of friction = centripetal force
$\frac{mv^{2}}{r} = \frac{100 \times (9)^{2}}{30} = 270\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.