Q.
The figure shows a circular path of a moving particle. If the velocity of the particle at same instant is $\mathbf{v} = - 3\widehat{\dot{\mathbf{i}}} - 4\widehat{\dot{\mathbf{j}}}$, through which quadrant is the particle moving when clockwise and anti-clockwise respectively
A) $1st\ and\ 4\ th$
B) $2nd\ and\ 4th$
C) $2\ nd\ and\ 3rd$
D) $3\ rd\ and\ 4\ th$
Explanation
(b) The figure shows a circular path of moving particle. At any instant velocity of particle.
[image:4_image165.emf]
$v = - 3\widehat{\dot{\mathbf{i}}} - 4\widehat{\dot{\mathbf{j}}} = ( - 3, - 4)$ (in coordinate from).
The coordinates of velocity show that particle is in 3rd quadrant at that instant. While moving clockwise particle will enter into 4th quadrant and these into 3rd and while moving anticlockwise particle will enter into 2nd quadrant and then into 3rd quadrant.
$\therefore 4th\ and\ 2nd\ quadrants.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.