Q. A particle of mass $M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its

A) Kinetic energy changes by $MV^{2}/4$
B) Momentum does not change
C) Momentum changes by $2MV$
D) Kinetic energy changes by $MV^{2}$
Explanation

The correct answer is Option C: Momentum changes by $2MV$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.