(b) $F^{2} = F^{2} + F^{2} + 2F^{2}cos\theta$ or $F^{2} = 2F^{2}(1 + cos\theta)$ or $1 + cos\theta = \frac{1}{2}$ or $cos\theta = - \frac{1}{2}$ or $\theta = 120{^\circ}$ $\therefore\ \cos 120{^\circ} = - \frac{1}{2}$
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Ph.D. in Physics with 19+ years of teaching experience.