Galileo writes that for angles of projection of a projectile at angles $(45 + heta)$ and $(45 - heta),\ $the horizontal ranges described by the projectile are in the ratio of $($if $ heta \leq 45)$

Question

Galileo writes that for angles of projection of a projectile at angles $(45 + 	heta)$ and $(45 - 	heta),\ $the horizontal ranges described by the projectile are in the ratio of $($if $	heta \leq 45)$

Dr. Abubacker · Accepted Answer

(c) For angle $(45{^\circ} - 	heta),R = \frac{u^{2}\sin(90{^\circ} - 2	heta)}{g} = \frac{u^{2}\cos{2	heta}}{g}$
For angle$\ (45{^\circ} + 	heta),\ R = \frac{u^{2}\sin(90{^\circ} + 2	heta)}{g} = \frac{u^{2}\cos{2	heta}}{g}$

Q. Galileo writes that for angles of projection of a projectile at angles $(45 + \theta)$ and $(45 - \theta),\ $the horizontal ranges described by the projectile are in the ratio of $($if $\theta \leq 45)$

Explanation

Reviewed by Dr. Abubacker

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