Q.
Three balls are dropped from the top of a building with equal speed at different angles. When the balls strike ground their velocities are $v_{1},{v\ }_{2}$ and $v_{3}$ respectively, then
A) $v_{1} > v_{2} > v_{3}$
B) $v_{3} > v_{2} > v_{1}$
C) $v_{1} = v_{2} = v_{3}$
D) $v_{1} < v_{2} < v_{3}$
Explanation
(c) All the balls are projected from the same height, therefore their velocities will be equal.
$So,\ v_{1} = v_{2} = v_{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.