Q. A cycle wheel of radius $0.4\ m$ completes one revolution in one $second$ then the acceleration of a point on the cycle wheel will be
A) $0.8\ m/s^{2}$
B) $0.4\ m/s^{2}$
C) $1.6\ \pi^{2}m/s^{2}$
D) $0.4\ \pi^{2}m/s^{2}$
Explanation
(c) Centripetal acceleration= $4\pi^{2}n^{2}r = 4\pi^{2} \times (1)^{2} \times 0.4 = 1.6\pi^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.