Q. The acceleration of a train travelling with speed of $400\ m/s$ as it goes round a curve of radius $160\ m$, is
A) $1\ km/s^{2}$
B) $100\ m/s^{2}$
C) $10\ m/s^{2}$
D) $1\ m/s^{2}$
Explanation
(a) $a = \frac{v^{2}}{r} = \frac{(400)^{2}}{160} = 10^{3}m/s^{2} = 1\ km/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.