(c) $h_{1} = \frac{v^{2}\sin^{2}\alpha}{2g},\ h_{2} = \frac{v^{2}\cos^{2}\alpha}{2g},\frac{h_{1}}{h_{2}} = \tan^{2}\alpha$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.