A projectile $A$ is thrown at an angle of $30{^\circ}$ to the horizontal from point $P$. At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A,\ \frac{v_{2}}{v_{1}}$ should be [image:4_image79.emf]

Question

Dr. Abubacker · Accepted Answer

(c) Equating velocities along the vertical,
$v_{2} = v_{1}\sin{30{^\circ}}\ or\ \ \ \frac{v_{2}}{v_{1}} = \frac{1}{2}$

Q. A projectile $A$ is thrown at an angle of $30{^\circ}$ to the horizontal from point $P$. At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A,\ \frac{v_{2}}{v_{1}}$ should be

Explanation

Reviewed by Dr. Abubacker

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