Q. A body is thrown horizontally from the top of a tower of height $5\ m$. It touches the ground at a distance of $10\ m$ from the foot of the tower. The initial velocity of the body is $(g = 10\ ms^{- 2})$
A) $2.5\ ms^{- 1}$
B) $5\ ms^{- 1}$
C) $10\ ms^{- 1}$
D) $20\ ms^{- 1}$
Explanation
(c) $S = u \times \sqrt{\frac{2h}{g}} \Rightarrow 10 = u\sqrt{2 \times \frac{5}{10}}\ \Rightarrow u = 10\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.