The mass of ship is $2 imes 10^{7}\ kg$. On applying a force of $25 imes 10^{5}\ N$ , it is displaced through $25\ m$. After the displacement, the velocity acquired by the ship will be

Question

The mass of ship is $2 	imes 10^{7}\ kg$. On applying a force of $25 	imes 10^{5}\ N$ , it is displaced through $25\ m$. After the displacement, the velocity acquired by the ship will be

Dr. Abubacker · Accepted Answer

(d) Here : Mass of ship $m = 2 	imes 10^{7}\ kg$,
Force $F = 25 	imes 10^{5}N$
Displacement $s = 25\ m$
According to the Newton’s second law of motion
$F = ma$
$\Rightarrow a = \frac{F}{m} = \frac{25 	imes 10^{5}}{2 	imes 10^{7}} = 12.5 	imes 10^{- 2}\ m/s^{2}$
The relation for final velocity is
$v^{2} = u^{2} + 2as\  \Rightarrow v^{2} = 0 + 2 	imes \left( 12.5 	imes 10^{- 2} ight) 	imes 25$
$\Rightarrow v = \sqrt{6.25} = 2.5\ m/s$

Q. The mass of ship is $2 \times 10^{7}\ kg$. On applying a force of $25 \times 10^{5}\ N$ , it is displaced through $25\ m$. After the displacement, the velocity acquired by the ship will be

Explanation

Reviewed by Dr. Abubacker

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