Q. If rope of lift breaks suddenly, the tension exerted by the surface of lift ($a =$ acceleration of lift)
A) $mg$
B) $m(g + a)$
C) $m(g - a)$
D) 0
Explanation
(d) If rope of lift breaks suddenly, acceleration becomes equal to $g$ so that tension, $T = m(g - g) = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.