Q. A lift of mass $1000\ kg$ is moving with an acceleration of $1\ m/s^{2}$ in upward direction. Tension developed in the string, which is connected to the lift is $(g = 9.8\ m/s^{2})$
A) $9,800\ N$
B) $10,000\ N$
C) $10,\ 800\ N$
D) $11,\ 000\ N$
Explanation
(c) $T = m(g + a) = 1000(9.8 + 1) = 10800\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.