Three blocks of masses $m_{1},m_{2}$ and $m_{3}$ are placed on a horizontal frictionless surface. A force of 40 N pulls the system then calculate the value of $T$, if $m_{1} = 10$ kg, $m_{2} = 6$ kg, $m_{3} = 4$ kg [image:5_image1.emf]

Question

Dr. Abubacker · Accepted Answer

(b) From the relation, acceleration
$a = \frac{F}{m_{1} + m_{2} + m_{3}}\ \  \Rightarrow \ a = \frac{40}{10 + 6 + 4} = 2ms^{- 2}$
$	herefore 40 - T = 10 	imes 2$
$T = 20$ N

Q. Three blocks of masses $m_{1},m_{2}$ and $m_{3}$ are placed on a horizontal frictionless surface. A force of 40 N pulls the system then calculate the value of $T$, if $m_{1} = 10$ kg, $m_{2} = 6$ kg, $m_{3} = 4$ kg

Explanation

Reviewed by Dr. Abubacker

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