The pulley and strings shown in figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle $ heta$ should be [image:5_image2.jpeg]

Question

The pulley and strings shown in figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle $	heta$ should be [image:5_image2.jpeg]

Dr. Abubacker · Accepted Answer

(c) If $T$ is tension in each part of the string holding mass $\sqrt{2}m$, then in equilibrium,
$T\cos{	heta + T\cos{	heta =}}\sqrt{2}\ m$g
${\ 2}{T\cos{	heta =}}\sqrt{2}\ m$g
But $T = mg;\ \ 	herefore 2mg\cos{	heta =}\sqrt{2}m$g
$\cos	heta = \frac{1}{\sqrt{2}}$
$	heta = 45{^\circ}$

Q. The pulley and strings shown in figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle $\theta$ should be

Explanation

Reviewed by Dr. Abubacker

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