(a) Let R be the reaction of base of lift and $g$ the acceleration due to gravity, acting downwards. Their resultant provides the net acceleration to the lift. Therefore,
$R - mg = ma$
$\Longrightarrow \ \ R = m(g + a)$
$Also,\ \ \ \ R = mg^{'}$
$\Longrightarrow \ \ \ g^{'} = g + a$
Therefore, net acceleration increases and hence, reading indicated by spring balance will increase.
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