Q. A body is moving along a rough horizontal surface with an initial velocity $6\ m/s$. If the body comes to rest after travelling $9m$, then the coefficient of sliding friction will be
A) 0.4
B) 0.2
C) 0.6
D) 0.8
Explanation
(b) We know $s = \frac{u^{2}}{2\mu\ g}\ \therefore\ \mu = \frac{u^{2}}{2gs} = \frac{(6)^{2}}{2 \times 10 \times 9} = 0.2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.