Q. A stick of $1\ m$ is moving with velocity of $2.7 \times 10^{8}\ ms^{- 1}$. What is the apparent length of the stick $(c = 3 \times 10^{8}\ ms^{- 1})$

A) $10\ m$
B) $0.22\ m$
C) $0.44\ m$
D) $2.4\ m$
Explanation

(c) $l = l_{0}\sqrt{1 - \frac{v^{2}}{c^{2}}} = 1\sqrt{1 - \left( \frac{2.7 \times 10^{8}}{3 \times 10^{8}} \right)^{2}}\ \Rightarrow l = 0.44\ m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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