Q. Sand is being dropped on a conveyor belt at the rate of $M\ kg/s$. The force necessary to keep the belt moving with a constant velocity of $v\ m/s$ will be
A) $\frac{Mv}{2}$ newton
B) Zero
C) $Mv$ newton
D) $2\ Mv$ newton
Explanation
(c) Force $= v\frac{dm}{dt}$
Force $= v\ M$ [$\therefore$ Force $= M\ v$ newton]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.