Q. A block of mass 2 kg rests on horizontal surface. If a horizontal force of 5 N is applied on the block, the frictional force on, it is $(\mu_{k} = 0.4,\ \mu_{s} = 0.5)$
A) 5 N
B) 10 N
C) 8 N
D) Zero
Explanation
(c) The frictional force F is given by
$F = \mu_{k\ }mg$
$Given,\mu_{k} = 0.4,\ m = 2\ kg,\ \ g = 10\ {ms}^{- 2}$
$\therefore F = 0.4 \times 2 \times 10$
$F = 8\ \ $N
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.