(b) $\left| \overrightarrow{F} \right| = \sqrt{5^{2} + 5^{2}} = 5\sqrt{2}\ N$ And $\tan\theta = \frac{5}{5} = 1$ $\Rightarrow \theta = \pi/4$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.