Q.
Two block of masses $7\ kg$ and $5\ kg$ are placed in contact with each other on a smooth surface. If a force of $6\ N$ is applied on the heavier mass, the force on the lighter mass is
A) $3.5\ N$
B) $2.5\ N$
C) $7\ N$
D) $5\ N$
Explanation
(b) Newton second law
$F = ma \Rightarrow 6 = (7 + 5)a\ ;a = \frac{1}{2}\frac{m}{s^{2}};F' \rightarrow 5\ kg$
Now, $F^{'} = 5 \times \frac{1}{2} = 2.5\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.