(c) Change of momentum F $\mathbf{\mathrm{\Delta}}t = m\mathrm{\Delta}\mathbf{v}$
$\mathbf{\Longrightarrow \ \ }\mathbf{F} = \frac{m\mathrm{\Delta}\mathbf{v}}{t}$
By doing so time of change in momentum increases and impulsive force on knees decreases.