Three blocks of masses $m_{1},m_{2}$ and $m_{3}$ are connected by massless strings as shown on a frictionless table in figure. They are pulled with a force $T_{3} = 40$ N. If $m_{1} = 10$ kg, $m_{2} = 6$ kg and $m_{3} = 4$ kg, the tension $T_{2}$ will be [image:5_image12.emf]

Question

Dr. Abubacker · Accepted Answer

(d) Common acceleration, $a = \frac{40}{10 + 6 + 4}ms^{- 2} = 2ms^{- 2}$
[image:5_image160.emf]
Now, $40 - T_{2} = 4 	imes 2$ or $T_{2} = (40 - 8)$N= 32 N

Q. Three blocks of masses $m_{1},m_{2}$ and $m_{3}$ are connected by massless strings as shown on a frictionless table in figure. They are pulled with a force $T_{3} = 40$ N. If $m_{1} = 10$ kg, $m_{2} = 6$ kg and $m_{3} = 4$ kg, the tension $T_{2}$ will be

Explanation

Reviewed by Dr. Abubacker

Want more practice?