
(c) $5g - T_{2} = 5a\ \ \ \ \ \ \ \ $….(i)
$T_{2} - T_{1} - 3g = 3a\ \ \ \ \ \ $…(ii)
$T_{1} - g = a\ \ \ \ \ \ \ \ $…(iii)
[image:5_image162.emf]
Adding Eqs (i) and (iii),
$- T_{2} + T_{1} + 4g = 6a$
Adding this to Eq. (ii), we get
$g = 9a$ or $a = \frac{g}{9}$
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