Q. A rod of length $L$ and weight $W$ is kept horizontally. A small weight $w$ is hung at one end. If the system balances on a fulcrum placed at $T$ then

A) $x = \frac{L}{2}$
B) $x = \frac{wL}{2(W + w)}$
C) $x = \frac{wL}{W}$
D) None of these
Explanation

The correct answer is Option B: $x = \frac{wL}{2(W + w)}$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Laws Of Motion MCQs