Q. A player caught a cricket ball of mass $150\ gm$ moving at the rate of $20\ m/sec$. If the catching process be completed in $0.1\ sec$ the force of the blow exerted by the ball on the hands of player is
A) $0.3\ N$
B) $30\ N$
C) $300\ N$
D) $3000\ N$
Explanation
(b) Force exerted by the ball
$\Rightarrow F = m\left( \frac{dv}{dt} \right) = 0.15 \times \frac{20}{0.1} = 30\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.