Q. A gun of mass $10\ kg$ fires 4 bullets per second. The mass of each bullet is $20\ g$ and the velocity of the bullet when it leaves the gun is $300\ ms^{- 1}$. The force required to hold the gum while firing is
A) $6\ N$
B) $8\ N$
C) $24\ N$
D) $240\ N$
Explanation
(c) Rate of change of momentum of the bullet in forward direction = Force required to hold the gun
$F = nmv = 4 \times 20 \times 10^{- 3} \times 300 = 24\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.