Q. In the above ques., the height to which the lift takes the passenger is
A) $3.6\ meters$
B) $8\ meters$
C) $1.8\ meters$
D) $36\ meters$
Explanation
(d) Distance travelled by the lift
= Area under velocity time graph
$= \left( \frac{1}{2} \times 2 \times 3.6 \right) + (8 \times 3.6) + \left( \frac{1}{2} \times 2 \times 3.6 \right) = 36\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.