Q. A false balance has equal arms. An object weigh $X$ when placed in one pan and $Y$ when placed in other pan, then the weight $W$ of the object is equal to
A) $\sqrt{XY}$
B) $\frac{X + Y}{2}$
C) $\frac{X^{2} + Y^{2}}{2}$
D) $\frac{2}{\sqrt{X^{2} + Y^{2}}}$
Explanation
(b) When false balance has equal arms then, $W = \frac{X + Y}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.