Q. A body of weight $2\ kg$ is suspended as shown in the figure. The tension $T_{1}$ in the horizontal string (in $kg\ wt$ ) is
A) $2/\sqrt{3}$
B) $\sqrt{3}/2$
C) $2\sqrt{3}$
D) $2$
Explanation
(c) $T\sin 30 = 2\ kg\ wt$
$\Rightarrow T = 4\ kg\ wt$
$T_{1} = T\cos{30{^\circ}}$
$= 4\cos{30{^\circ}}$
$= 2\sqrt{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.